How to print a dictionary line by line in Python?

You could use the json module for this. The dumps function in this module converts a JSON object into a properly formatted string which you can then print.

import jsoncars = {'A':{'speed':70, 'color':2},'B':{'speed':60, 'color':3}}print(json.dumps(cars, indent = 4))

The output looks like

{"A": {"color": 2,"speed": 70},"B": {"color": 3,"speed": 60}}

The documentation also specifies a bunch of useful options for this method.

A more generalized solution that handles arbitrarily-deeply nested dicts and lists would be:

def dumpclean(obj):if isinstance(obj, dict):for k, v in obj.items():if hasattr(v, '__iter__'):print kdumpclean(v)else:print '%s : %s' % (k, v)elif isinstance(obj, list):for v in obj:if hasattr(v, '__iter__'):dumpclean(v)else:print velse:print obj

This produces the output:

Acolor : 2speed : 70Bcolor : 3speed : 60

I ran into a similar need and developed a more robust function as an exercise for myself. I'm including it here in case it can be of value to another. In running nosetest, I also found it helpful to be able to specify the output stream in the call so that sys.stderr could be used instead.

import sysdef dump(obj, nested_level=0, output=sys.stdout):spacing = ' 'if isinstance(obj, dict):print >> output, '%s{' % ((nested_level) * spacing)for k, v in obj.items():if hasattr(v, '__iter__'):print >> output, '%s%s:' % ((nested_level + 1) * spacing, k)dump(v, nested_level + 1, output)else:print >> output, '%s%s: %s' % ((nested_level + 1) * spacing, k, v)print >> output, '%s}' % (nested_level * spacing)elif isinstance(obj, list):print >> output, '%s[' % ((nested_level) * spacing)for v in obj:if hasattr(v, '__iter__'):dump(v, nested_level + 1, output)else:print >> output, '%s%s' % ((nested_level + 1) * spacing, v)print >> output, '%s]' % ((nested_level) * spacing)else:print >> output, '%s%s' % (nested_level * spacing, obj)

Using this function, the OP's output looks like this:

{A:{color: 2speed: 70}B:{color: 3speed: 60}}

which I personally found to be more useful and descriptive.

Given the slightly less-trivial example of:

{"test": [{1:3}], "test2":[(1,2),(3,4)],"test3": {(1,2):['abc', 'def', 'ghi'],(4,5):'def'}}

The OP's requested solution yields this:

test1 : 3test3(1, 2)abcdefghi(4, 5) : deftest2(1, 2)(3, 4)

whereas the 'enhanced' version yields this:

{test:[{1: 3}]test3:{(1, 2):[abcdefghi](4, 5): def}test2:[(1, 2)(3, 4)]}

I hope this provides some value to the next person looking for this type of functionality.

pprint.pprint() is a good tool for this job:

>>> import pprint>>> cars = {'A':{'speed':70,... 'color':2},... 'B':{'speed':60,... 'color':3}}>>> pprint.pprint(cars, width=1){'A': {'color': 2,'speed': 70},'B': {'color': 3,'speed': 60}}

You have a nested structure, so you need to format the nested dictionary too:

for key, car in cars.items():print(key)for attribute, value in car.items():print('{} : {}'.format(attribute, value))

This prints:

Acolor : 2speed : 70Bcolor : 3speed : 60

I prefer the clean formatting of yaml:

import yamlprint(yaml.dump(cars))

output:

A:color: 2speed: 70B:color: 3speed: 60

for car,info in cars.items():print(car)for key,value in info.items():print(key, ":", value)

This will work if you know the tree only has two levels:

for k1 in cars:print(k1)d = cars[k1]for k2 in dprint(k2, ':', d[k2])

Check the following one-liner:

print('\n'.join("%s\n%s" % (key1,('\n'.join("%s : %r" % (key2,val2) for (key2,val2) in val1.items()))) for (key1,val1) in cars.items()))

Output:

Aspeed : 70color : 2Bspeed : 60color : 3

Here is my solution to the problem. I think it's similar in approach, but a little simpler than some of the other answers. It also allows for an arbitrary number of sub-dictionaries and seems to work for any datatype (I even tested it on a dictionary which had functions as values):

def pprint(web, level):for k,v in web.items():if isinstance(v, dict):print('\t'*level, f'{k}: ')level += 1pprint(v, level)level -= 1else:print('\t'*level, k, ": ", v)

Made one liner. Outputs exactly what you want.

cars = {'A':{'speed':70,'color':2},'B':{'speed':60,'color':3}}print('\n'.join(f'{k}\n'+'\n'.join(f'{k2} : {v}' for k2,v in reversed(cars[k].items())) for k in reversed(cars)))

Also, tried run with timeit all solutions. And mine was always slowest.

###newbie exact answer desired (Python v3):###================================="""cars = {'A':{'speed':70,'color':2},'B':{'speed':60,'color':3}}"""for keys, values in reversed(sorted(cars.items())):print(keys)for keys,values in sorted(values.items()):print(keys," : ", values)"""Output:Bcolor : 3speed : 60Acolor : 2speed : 70##[Finished in 0.073s]"""

# Declare and Initialize Mapmap = {}map ["New"] = 1map ["to"] = 1map ["Python"] = 5map ["or"] = 2# Print Statementfor i in map:print ("", i, ":", map[i])# New : 1# to : 1# Python : 5# or : 2

Use this.

cars = {'A':{'speed':70,'color':2},'B':{'speed':60,'color':3}}print(str(cars).replace(",", ",\n"))

output:

{'A': {'speed': 70,'color': 2},'B': {'speed': 60,'color': 3}}

I think list comprehension is the cleanest way to do this:

mydict = {a:1, b:2, c:3}[(print("key:", key, end='\t'), print('value:', value)) for key, value in mydict.items()]

Modifying MrWonderful code

import sysdef print_dictionary(obj, ident):if type(obj) == dict:for k, v in obj.items():sys.stdout.write(ident)if hasattr(v, '__iter__'):print kprint_dictionary(v, ident + ' ')else:print '%s : %s' % (k, v)elif type(obj) == list:for v in obj:sys.stdout.write(ident)if hasattr(v, '__iter__'):print_dictionary(v, ident + ' ')else:print velse:print obj