If-else statement inside jsx: ReactJS

You can achieve what you are saying by using Immediately Invoked Function Expression (IIFE)

render() {return ( <View style={styles.container}>{(() => {if (this.state == 'news'){return (<Text>data</Text>)}return null;})()}</View>)}

Here is the working example:

But, In your case, you can stick with the ternary operator

I find this way is the nicest:

{this.state.yourVariable === 'news' && <Text>{data}<Text/>}

I do like this and its working fine.

constructor() {super();this.state ={status:true}}render() {return( { this.state.status === true ?<TouchableHighlight onPress={()=>this.hideView()}><View style={styles.optionView}><Text>Ok Fine :)</Text></View></TouchableHighlight>:<Text>Ok Fine.</Text>});}hideView(){this.setState({home:!this.state.status});}

You can do this. Just don't forget to put "return" before your JSX component.

Example:

render() {if(this.state.page === 'news') {return <Text>This is news page</Text>;} else {return <Text>This is another page</Text>;}}

Example to fetch data from internet:

import React, { Component } from 'react';import {View,Text} from 'react-native';export default class Test extends Component {constructor(props) {super(props);this.state = {bodyText: ''}}fetchData() {fetch('https://example.com').then((resp) => {this.setState({bodyText: resp._bodyText});});}componentDidMount() {this.fetchData();}render() {return <View style={{ flex: 1 }}><Text>{this.state.bodyText}</Text></View>}}

There's a Babel plugin that allows you to write conditional statements inside JSX without needing to escape them with JavaScript or write a wrapper class. It's called JSX Control Statements:

<View style={styles.container}><If condition={ this.state == 'news' }><Text>data</Text></If></View>

It takes a bit of setting up depending on your Babel configuration, but you don't have to import anything and it has all the advantages of conditional rendering without leaving JSX which leaves your code looking very clean.

What about switch case instead of if-else

 render() {switch (this.state.route) {case 'loginRoute':return (<Login changeRoute={this.changeRoute}changeName={this.changeName}changeRole={this.changeRole} />);case 'adminRoute':return (<DashboardAdminrole={this.state.role}name={this.state.name}changeRoute={this.changeRoute}/>);default: return <></>;}

There is no need for the if else condition in JSX. It provides a function like ternary operator to make the thing happen for you, example:

state={loading:false}<View>{loading ? <Text>This is a test For if else condition</Text> : <ActivityIndicator/></View>

 <Card style={{ backgroundColor: '#ffffff', height: 150, width: 250, paddingTop: 10 }}><Text style={styles.title}> {item.lastName}, {item.firstName} ({item.title})</Text> <Text > Email: {item.email}</Text>{item.lastLoginTime != null ? <Text > Last Login: {item.lastLoginTime}</Text> : <Text > Last Login: None</Text>}{item.lastLoginTime != null ? <Text > Status: Active</Text> : <Text > Status: Inactive</Text>} </Card>

If you want to use an conditional statement in functional component then you can call a function from jsx and put all your conditional logic inside it.

conditionalRender(){if(state === 'news') {return <Text>data</Text>;}else(state !== 'news') {return <Text>Static Value</Text>;}}render() {return ( <View style={styles.container}>{ conditionalRender() }</View>)}

 render() {return ( <View style={styles.container}>(() => { if (this.state == 'news') {return <Text>data</Text>}else return <Text></Text>})()</View>)}

https://react-cn.github.io/react/tips/if-else-in-JSX.html

Simple example of nested loop with if condition in React:

Data example:

 menus: [{id:1, name:"parent1", pid: 0},{id:2, name:"parent2", pid: 0},{id:3, name:"parent3", pid: 0},{id:4, name:"parent4", pid: 0},{id:5, name:"parent5", pid: 0},{id:6, name:"child of parent 1", pid: 1},{id:7, name:"child of parent 2", pid: 2},{id:8, name:"child of parent 2", pid: 2},{id:9, name:"child of parent 1", pid: 1},{id:10, name:"Grand child of parent 2", pid: 7},{id:11, name:"Grand child of parent 2", pid: 7},{id:12, name:"Grand child of parent 2", pid: 8},{id:13, name:"Grand child of parent 2", pid: 8},{id:14, name:"Grand child of parent 2", pid: 8},{id:15, name:"Grand Child of Parent 1 ", pid: 9},{id:15, name:"Child of Parent 4 ", pid: 4},]

Nested Loop and Condition:

 render() {let subMenu='';let ssubmenu='';const newMenu = this.state.menus.map((menu)=>{if (menu.pid === 0){return (<ul key={menu.id}><li>{menu.name}<ul>{subMenu = this.state.menus.map((smenu) => {if (menu.id === smenu.pid) {return (<li>{smenu.name}<ul>{ssubmenu = this.state.menus.map((ssmenu)=>{if(smenu.id === ssmenu.pid){return(<li>{ssmenu.name}</li>)}})}</ul></li>)}})}</ul></li></ul>)}})return (<div>{newMenu}</div>);}}

You can't provide if-else condition in the return block, make use of ternary block, also this.state will be an object, you shouldn't be comparing it with a value, see which state value you want to check, also return returns only one element, make sure to wrap them in a View

render() {return (<View style={styles.container}>{this.state.page === 'news'? <Text>data</Text>: null}</View>)}

In two ways we can solve this problem:

1. Write a else condition by adding just empty <div> element.
2. or else return null.

render() {return ( <View style={styles.container}>if (this.state == 'news'){return (<Text>data</Text>);}else {<div> </div>}</View>)}

Just Tried that:

return(<>{main-condition-1 && main-condition-2 &&(sub-condition ? (<p>Hi</p>) : (<p>Hello</p>))}</>)

Let me know what you guys think!!!

Just Write Down The Code

 <> {row.photo != null ? <img src={serverPath(row.photo)} className='img-fluid shadow-4' alt="" /> : ''}</>

For this we can use ternary operator or if there is only one condition then "&&" operator .Like this:-

//This is for if elserender() {return ( <View style={styles.container}>{this.state == 'news') ?<Text>data</Text>: null}</View>)

}

//This is only for if or only for one conditionrender() {return ( <View style={styles.container}>{this.state == 'news') &&<Text>data</Text>}</View>)

}